Video What number must be added to each of the numbers 711 and 19 so that the resulting numbers may be in continued proportion? ?
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Bùi Phạm Vân Anh đang tìm kiếm từ khóa What number must be added to each of the numbers 711 and 19 so that the resulting numbers may be in continued proportion? được Update vào lúc : 2022-10-03 09:35:21 . Với phương châm chia sẻ Bí kíp về trong nội dung bài viết một cách Chi Tiết 2022. Nếu sau khi tham khảo Post vẫn ko hiểu thì hoàn toàn có thể lại phản hồi ở cuối bài để Admin lý giải và hướng dẫn lại nha.ML Aggarwal Solutions Class 10 Mathematics Solutions for Ratio and Proportion Exercise 7.2 in Chapter 7 - Ratio and Proportion
Question 6 Ratio and Proportion Exercise 7.2
Nội dung chính- ML Aggarwal Solutions Class 10 Mathematics Solutions for Ratio and Proportion Exercise 7.2 in Chapter 7 - Ratio and Proportion ML Aggarwal Solutions Class 10 Mathematics Solutions for Ratio and Proportion Exercise 7.2 in Chapter 7 - Ratio and Proportion 1. What must be added to each of the numbers 7, 11 and 19, so that the resulting numbers may be in continued proportion?Answer & SolutionWhat number must be added to each of the numbers 7, 4 and 2 so that the resulting numbers may be in a continued proportion?Answer
(Detailed Solution Below)What must be added to each of the number 711 and 19 so that the resulting numbers may be in the continued proportion?What number must be added to each of the number 5 9 7 12 to get the numbers which are in proportion?What number must be added to each of the numbers 7 4 and 2 so that the resulting number may be in a continued proportion?What must be added to each of the numbers 7/10 19 25 so that the resultant numbers are in proportion?
What number must be added to each of the numbers 5, 11, 19, and 37 so that they are in proportion?
Answer:
Consider x to be added to 5, 11, 19 and 37 to make them in proportion
5 + x: 11 + x :: 19 + x: 37 + x
It can be written as
(5 + x) (37 + x) = (11 + x) (19 + x)
By further calculation
beginarrayl 185+5 x+37 x+x^2=209+11 x+19 x+x^2 \ 185+42 x+x^2=209+30 x+x^2 endarray
So we get
42 x-30 x+x^2-x^2=209-185
12x = 24
x = 2
Hence, the least number to be added is 2.
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ML Aggarwal Solutions Class 10 Mathematics Solutions for Ratio and Proportion Exercise 7.2 in Chapter 7 - Ratio and Proportion
Question 10 Ratio and Proportion Exercise 7.2
What number must be added to each of the numbers 16, 26, and 40 so that the resulting numbers may be in continued proportion?
Answer:
Consider x be added to each number
16 + x , 26 + x and 40 + x are in continued proportion
It can be written as
(16 + x)/ (26 + x) = (26 + x)/ (40 + x)
By cross multiplication
(16 + x) (40 + x) = (26 + x) (26 + x)
On further calculation
beginarrayl 640+16 x+40 x+x^2=676+26 x+26 x+x^2 \ 640+56 x+x^2=676+52 x+x^2 \ 56 x+x^2-52 x-x^2=676-640 endarray
So we get
4x = 36
x = 36/4 = 9
Hence, 9 is the number to be added to each of the numbers.
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1. What must be added to each of the numbers 7, 11 and 19, so that the resulting numbers may be in continued proportion?
1.
2.
3.
4.
Answer & Solution

Answer & Solution
Answer: Option 4
Solution:
Let X be the required number, then
(7 + X) : (11 + X) :: (11 +X) : (19 + X)
(7 + X) (19 + X) = (11 + X)2
X2 + 26X + 133 = X2 + 22X + 121
4X = - 12 or X = - 3
What number must be added to each of the numbers 7, 4 and 2 so that the resulting numbers may be in a continued proportion?
This question was previously asked in
SSC MTS 2022 (Held On : 11 Oct 2022 Shift 3 ) Official Paper 15
View all SSC MTS Papers >
2435Answer (Detailed Solution Below)
Option 1 : 2
Free
CT : GK (Ancient History)
10 Questions 10 Marks 6 Mins
Given
7,4 and 2 should be in a continued proportion
Concept
Continued proportion means the ratio between the first and the second is equal to the ratio between the second and the third
Calculation
let x is added in each number
(7 + x)/(4 + x) = (4 + x)/(2 + x)
⇒ (7 + x) (2 + x) = (4 + x) (4 + x)
⇒ 14 + 7x + 2x + x2 = 16 + 8x + x2
⇒ 14 + 9x + x2 = 16 + 8x + x2
⇒ 14 + 9x = 16 + 8x
⇒ 9x - 8x = 16 - 14
⇒ x = 2
∴ 2 must be added to each of the numbers 7, 4 and 2 so that the resulting numbers may be in a continued proportion.
Last updated on Sep 28, 2022
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